Assumptions, a refresher and some definitions

This week there are certain assumptions that must be accepted to simplify the training delivery.

Unless you are clearly told otherwise assume:

A quick reminder here that this week is not about the maths – most question answers have a range. It’s important you get the well control correct… not the absolute arithmetical answer.

Except…

Kill Mud Weight – one decimal place rounded UP – every time

Maximum mud weight – one decimal AS CALCULATED – every time

Everything else round mathematically.

Well control understanding revolves around hydrostatic pressure and the U-tube principle. A good grasp of the hydrostatic pressure formula and its variations will go a long way in helping with your understanding of well control. The U-tube principle we simply must accept as we do not have the time available to conduct enough experiments to prove it. More on that later.

As with all formulas the important bit is not the words in the formula but the bit in brackets – the units – so stripping away the words for Hydrostatic Pressure (formula 1 on the IWCF formula sheet) we get:

psi=ppg×0.052×ft\text{psi} = \text{ppg} \times 0.052 \times \text{ft}

You can work out any pressure if you know the mud density in ppg and the true vertical depth in ft. Using basic algebra, we can re-arrange this formula to get two variations on it namely:

ppg=psi÷ft÷0.052\text{ppg} = \text{psi} \div \text{ft} \div 0.052

and

ft=psi÷ppg÷0.052\text{ft} = \text{psi} \div \text{ppg} \div 0.052

There is a relationship in a well between the pressure at the bottom of the well, the mud density in the well and the true vertical height of that mud column as shown below:

To work out pressure you multiply and that can be done in any order – for the two variations you must start with PRESSURE the divide by DENSITY or DEPTH the divide by the CONSTANT to get:

That was the refresher by the way.

And so, to some definitions for the week.

This week we assume normal formation pressure has a gradient of 0.465psi/ft0.465 \text{psi} / \text{ft}